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0.orig | ||
constant | ||
system | ||
Allclean | ||
Allrun | ||
README.md |
Reference:
Figueiredo, R. A., Oishi, C. M., Afonso, A. M., Tasso, I. V. M., &
Cuminato, J. A. (2016).
A two-phase solver for complex fluids: Studies of the Weissenberg effect.
International Journal of Multiphase Flow, 84, 98-115.
In compressibleInterFoam with turbulenceProperties simulationType set to twoPhaseTransport separate stress models (laminar, non-Newtonian, LES or RAS) are instantiated for each of the two phases allowing for different modeling for the phases.
This example case uses:
- phases "air" and "liquid"
- air phase
- constant/turbulenceProperties.air:
- stress model set to laminar, Newtonian
- constant/thermophysicalProperties.air:
- transport set to const (Newtonian)
- mu (dynamic viscoity) = 1.84e-5
- constant/turbulenceProperties.air:
- liquid phase
- constant/turbulenceProperties.liquid:
- stress model set to laminar, Maxwell non-Newtonian
- nuM (kinematic viscosity) = 0.01476
- lambda = 0.018225
- constant/thermophysicalProperties.liquid
- transport set to const (Newtonian)
- mu (dynamic viscoity) = 1.46
- constant/turbulenceProperties.liquid:
Liquid phase properties were calculated from the relations given in the paper:
- rho = 890 kg/m^3
- mu = mu_{s} + mu_{p} = 146 poise = 14.6 Pa.s s = solvent (Newtonian), p = polymer (Maxwell)
- mu_{s}/mu_{p} = 1/9
=> mu_{s} = 14.6/10 = 1.46 Pa.s => nu_{p} = nuM = (9/10)*14.6/890 = 0.01476 m^2/s
compressibleInterFoam solves the energy equation, despite not being needed in this example. The case is simply initialised at a uniform temperature of 300K throughout the domain and at the atmosphere boundary.